4[6-(3z+1)]+19=3(4-z)

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Solution for 4[6-(3z+1)]+19=3(4-z) equation:


Simplifying
4[6 + -1(3z + 1)] + 19 = 3(4 + -1z)

Reorder the terms:
4[6 + -1(1 + 3z)] + 19 = 3(4 + -1z)
4[6 + (1 * -1 + 3z * -1)] + 19 = 3(4 + -1z)
4[6 + (-1 + -3z)] + 19 = 3(4 + -1z)

Combine like terms: 6 + -1 = 5
4[5 + -3z] + 19 = 3(4 + -1z)
[5 * 4 + -3z * 4] + 19 = 3(4 + -1z)
[20 + -12z] + 19 = 3(4 + -1z)

Reorder the terms:
20 + 19 + -12z = 3(4 + -1z)

Combine like terms: 20 + 19 = 39
39 + -12z = 3(4 + -1z)
39 + -12z = (4 * 3 + -1z * 3)
39 + -12z = (12 + -3z)

Solving
39 + -12z = 12 + -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
39 + -12z + 3z = 12 + -3z + 3z

Combine like terms: -12z + 3z = -9z
39 + -9z = 12 + -3z + 3z

Combine like terms: -3z + 3z = 0
39 + -9z = 12 + 0
39 + -9z = 12

Add '-39' to each side of the equation.
39 + -39 + -9z = 12 + -39

Combine like terms: 39 + -39 = 0
0 + -9z = 12 + -39
-9z = 12 + -39

Combine like terms: 12 + -39 = -27
-9z = -27

Divide each side by '-9'.
z = 3

Simplifying
z = 3

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